CS302 Assignment 1 Solution 2021 - Digital Logic Design Assignment

 CS302 Assignment 1 Solution Spring 2021

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View CS302 Assignment No 1 Solution Fall 2021 

Total Marks: 20

Due Date: 24-May-2021

QUESTION 1:

You are required to perform stated operations. You must consider the stated bases or number system for your final answer.

You can use indirect conversion or repeated division methods only. Your solution must have to list down all the steps of calculations and conversions involved. In the case of direct results, major marks will be deducted.

Question Part 1.ΩΩ∑↑↑∆>C+↑>Ω∆∆ΩC=C=H

SOLUTION:

Ω	3
Ω	3
∑	0
	4
	4
∆	1
>	2

	4
>	2
Ω	3
∆	1
∆	1
Ω	3

3304412+423113

(3727525)10 = (Ω∆∆>∆>∆)C

16	3727525
16	232970 - 5
16	14560 - 10
16	910 - 0
16	56 – 14
	3 - 8

(3727525)10 = (38E0A5)11

Question Part 2. FDEA2H-8989FH+767657O=H

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SOLUTION:

F	15
D	13
E	14
A	10
2	2

8	8
9	9
8	8
9	9
F	15

7	7
6	6
7	7
6	6
5	5
7	7

(151314102)10 – (898915)10 – (765677)10 = (?)H

(150415187)10 + (767657)10 = (?)H

(1511182844)10 = (?)H

16	151182844
16	9448927 – 12
16	590577 – 15
16	36909 – 13
16	2606 – 13
16	144 - 2
	9 - 0

(1511182844)10 = (902DDFC)H

ANSWER.

QUESTION 2:

Perform the following conversions:

Question Part 1) 

-831.696972

SOLUTION:

2	831
2	415 - 1
2	27 – 1
2	13 – 1
2	6 – 1
2	3 – 0
	1 – 1

• 831 = (-1101111)

.696972×2 = 1.393944

.393944×2 = 0.787889

.787889×2 = 1.575778

.575778×2 = 1.151552

.151552×2 = 0.303105

. 696972 = .10110

-831.696972 = (-1101111.10110)2

Question Part 2)

 (0 10000111 11111111010100010101011)2

SOLUTION:

0×231+1×230+0×229+0×228+0×227+0×226+1×225+1×224+1×223+1×222+1×221+1×220+1×219+1×218+1×217+1×216+1×215+0×214+1×213+0×212+1×211+0×210+0×29+0×28+1×27+0×26+1×25+0×24+1×23+0×22+1×21+1×20

0+10737441824+0+0+0+33554432+16777216+8388608+4194304+2097152+1048576+524288+262144+131072+65536+32768+0+8192+0+2048+0+0+0+128+0+32+0+8+0+2+1

= 1140828331

(0 10000111 11111111010100010101011)2 = (1140828331)10

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