CS609 Current Final Term Paper 2022 - VU Answer

CS609 Current Final Term Papers 2022

Are you looking at CS609 Current Final term Paper 2022? If yes, then you visit the right site. We Provide CS609 Current Papers 2022. CS609 Final term Past Papers 2022 Mega File.

 

Students must prepare these cs609 finalterm current papers 2022. Also, it can give cs609 final term preparation 2022 important topics, questions, and an overview of the paper with downloads pdf files below.


CS609 CURRENT FINAL TERM PAPER 2022 

Provide by VU Answer


CS609 Paper

MCQS:

Each addressable unit has a unique combination of sec#, head# and track# as its address.

Highest physical capacity of the disk according to the IDE interface is approximately:

Partition Table can be read using the extended

the first block on disk

On a single disk there can be different Operating System

first physical block within extended partition

boot block constitutes of BPB


Subjective:

1. Com file typically have a single three bytes near jump instruction as the 1st instruction write down its purpose?

2. Absread() and abswrite() function used for?


See Also Below Links:


CS614 Current Final Term Paper 2022


CS607 Current Final Term Paper 2022


CS609 Final Term Solved Papers by Moaaz

CS609 Highlighted Handouts PDF


CS609 Short Notes for Final


CS609 Final Term Solved Papers by Waqar


3. Purpose of partition signature table?

4. Fat based system, how the content of a file can be accessed

5. Two reasons of covert a cluster number into sector number

6. How scan disk identified bad sector by using surface scan




Check Also Most Important Materials: 


All VU MCQs Final Term Solved Files - DOWNLOAD


VU Final Term Past Papers by Moaaz - DOWNLOAD


VU Short Notes PDF for Final - DOWNLOAD


VU Current Final Term Papers 2022 - DOWNLOAD

VU Final Term Past Papers by Waqar Siddhu - DOWNLOAD


Subject Wise All VU Handouts PDF - DOWNLOAD
 


  

Cs609


Q1) suppose we read the contents of Drive parameter block and get the following information.

Number of reserved blocks=2 

Number of blocks in FAT= 7 


Number of blocks in root directory=32 


Find the number of systems blocks. make the appropriate assumptions when needed.



Click Here to Download File

 

Note:

Papers shared by VU Answer and Students.

 

Share with fellows and help others in their studies.


Post a Comment

0 Comments